Q.Write the solution set of the
equation x^2+x-2=0 in roster form.
Please answer will full explanation
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Answer:2+2x-x-2 = 0
x(x+2)-1(x+2)
(x+2) (x-1)
x = -2 or x = 1
Roster form: {1,-2}
Step-by-step explanation:
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