Question

❒Qᴜᴇꜱᴛɪᴏɴ:-
•ʙʟᴜᴇ ʀᴏᴅ = x + 1
•ʀᴇᴅ ʀᴏᴅ = x + 2
•ɢʀᴇᴇɴ ʀᴏᴅ = 2x + 1
•ʏᴇʟʟᴏᴡ ʀᴏᴅ = 3x

ꜱʜᴏᴡ ᴛʜᴀᴛ-
➥ ᴛʜᴇ ᴛᴏᴛᴀʟ ʟᴇɴɢᴛʜ ᴏꜰ 2 ʏᴇʟʟᴏᴡ ʀᴏᴅꜱ ᴀɴᴅ 2 ʀᴇᴅ ʀᴏᴅꜱ ɪꜱ ꜱᴀᴍᴇ ᴀꜱ 4 ɢʀᴇᴇɴ ʀᴏᴅꜱ

➥ᴛʜᴇ ᴛᴏᴛᴀʟ ʟᴇɴɢᴛʜ ᴏꜰ 3 ʀᴇᴅ ʀᴏᴅꜱ ᴀɴᴅ 3 ʏᴇʟʟᴏᴡ ʀᴏᴅꜱ ɪꜱ ꜱᴀᴍᴇ ᴀꜱ 6 ɢʀᴇᴇɴ ʀᴏᴅꜱ

➥ᴛʜᴇ ᴛᴏᴛᴀʟ ʟᴇɴɢᴛʜ ᴏꜰ 4 ʀᴇᴅ ʀᴏᴅꜱ ᴀɴᴅ 4 ʏᴇʟʟᴏᴡ ʀᴏᴅꜱ ɪꜱ ꜱᴀᴍᴇ ᴀꜱ 8 ɢʀᴇᴇɴ ʀᴏᴅꜱ

❒ɴᴇᴇᴅ ᴄᴏʀʀᴇᴄᴛ ᴀɴꜱᴡᴇʀ
❒ɴᴏ ᴄᴏᴘɪᴇᴅ ᴀɴꜱᴡᴇʀ
❒ɴᴇᴇᴅ ꜱᴛᴇᴘ ʙʏ ꜱᴛᴇᴘ ᴇxᴘʟᴀɴᴀᴛɪᴏɴ

ᴀʟʟ ᴛʜᴇ ʙᴇꜱᴛ !

Answer 1

,$\huge\tt\red{࿐}\tt\pink{—>}\tt\blue{A}\tt\green{N}\tt\purple{S}\tt\orange{W}\tt\orange{E}\huge\tt\red{R}$,

(i) 5(2x + 1) (3x + 5) ÷ (2x + 1)

(ii) 26xy(x + 5)(y – 4) ÷ 13x(y – 4)

(iii) 52pqr (p + q) (q + r) (r + p) ÷ 104pq(q + r) (r + p)

(iv) 20\left(y+4\right)\left(y^2+5y+3\right)\div5\left(y+4\right)20(y+4)(y

2

+5y+3)÷5(y+4)

(v) x(x + 1) (x + 2) (x + 3) ÷ x(x + 1)

Solution 4:

(i) \frac{5\left(2x+1\right)\left(3x+5\right)}{2x+1}

2x+1

5(2x+1)(3x+5)

= 5(3x+5)

(ii) \frac{2\times13\times x\times y\times\left(x+5\right)\times\left(y-4\right)}{13\times x\times\left(y-4\right)}

13×x×(y−4)

2×13×x×y×(x+5)×(y−4)

=2\times y\times\left(x+5\right)2×y×(x+5)

=2y\left(x+5\right)2y(x+5)

(iii) \frac{2\times2\times13\times p\times q\times r\times\left(p+q\right)\times\left(q+r\right)\times\left(r+p\right)}{2\times2\times2\times13\times p\times q\times\left(q+p\right)\times\left(r+p\right)}

2×2×2×13×p×q×(q+p)×(r+p)

2×2×13×p×q×r×(p+q)×(q+r)×(r+p)

=\frac{r\left(p+q\right)}{2}

2

r(p+q)

(iv) \frac{20\left(y+4\right)\left(y^2+5y+3\right)}{5\left(y+4\right)}

5(y+4)

20(y+4)(y

2

+5y+3)

=4\left(y^2+5y+3\right)4(y

2

+5y+3)

(v)\frac{x\left(x+1\right)\left(x+2\right)\left(x+3\right)}{x\left(x+1\right)}

x(x+1)

x(x+1)(x+2)(x+3)

(x+2)(x+3)

Hope it helps u

Mark me as brainliest

꧁༺DҽѵíӀ ցíɾӀ༻꧂

Answer 2

❒ɢɪᴠᴇɴ-

➝ʙʟᴜᴇ ʀᴏᴅ = x + 1

➝ʀᴇᴅ ʀᴏᴅ = x + 2

➝ɢʀᴇᴇɴ ʀᴏᴅ = 2x + 1

➝ʏᴇʟʟᴏᴡ ʀᴏᴅ = 3x

➤ꜱʜᴏᴡ ᴛʜᴀᴛ:

➥ᴛʜᴇ ᴛᴏᴛᴀʟ ʟᴇɴɢᴛʜ ᴏꜰ 2 ʏᴇʟʟᴏᴡ ʀᴏᴅꜱ ᴀɴᴅ 2 ʀᴇᴅ ʀᴏᴅꜱ ɪꜱ ꜱᴀᴍᴇ ᴀꜱ 4 ɢʀᴇᴇɴ ʀᴏᴅꜱ

➾ 2 (x + 2) + 2 (3x) = 4 (2x + 1)

➾2x + 4 + 6x = 8x + 4

➾2x + 6x + 4 = 8x + 4

➾8x + 4 = 8x + 4

➥ᴛʜᴇ ᴛᴏᴛᴀʟ ʟᴇɴɢᴛʜ ᴏꜰ 3 ʀᴇᴅ ʀᴏᴅꜱ ᴀɴᴅ 3 ʏᴇʟʟᴏᴡ ʀᴏᴅꜱ ɪꜱ ꜱᴀᴍᴇ ᴀꜱ 6 ɢʀᴇᴇɴ ʀᴏᴅꜱ.

➾ 3 (x + 2) + 3 (3x) = 6 (2x + 1)

➾ 3x + 6 + 9x = 12x + 6

➾ 3x + 9x + 6 = 12x + 6

➾ 12x + 6 = 12x + 6

➥ᴛʜᴇ ᴛᴏᴛᴀʟ ʟᴇɴɢᴛʜ ᴏꜰ 4 ʀᴇᴅ ʀᴏᴅꜱ ᴀɴᴅ 4 ʏᴇʟʟᴏᴡ ʀᴏᴅꜱ ɪꜱ ꜱᴀᴍᴇ ᴀꜱ 8 ɢʀᴇᴇɴ ʀᴏᴅꜱ

➾ 4 (x + 2) + 4 (3x) = 8 (2x + 1)

➾ 4x + 8 + 12x = 16x + 8

➾ 4x + 12x + 8 = 16x + 8

➾ 16x + 8 = 16x + 8

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