Question

Qᴜᴇꜱᴛɪᴏɴ:-


ᴇxᴘʀᴇꜱꜱ ᴛʜᴇ ᴛʀɪɢᴏɴᴏᴍᴇᴛʀɪᴄ ʀᴀᴛɪᴏꜱ ꜱɪɴ ᴀ,ꜱᴇᴄ ᴀ ᴀɴᴅ ᴛᴀɴ ᴀ ɪɴ ᴛᴇʀᴍꜱ ᴏꜰ ᴄᴏᴛ ᴀ.​

Answer 1

Answer:

Tan A = 1/ cot A

we know that,

1+ tan²A= sec²A

1+1/cot²A=sec²A

√1+1/cot²A=secA

√cot²A+1/cot²A=secA

so, secA=√cot²A+1/cotA

1+ cot²A=cosec²A

cosec²A=1+cot²A

cosecA=√1+cot²A

now,

sinA=1/cosecA

sinA=1/(√1+cot²A)