Question

Q- (x² + 1)² - x²=0 has
a. four real roots
b. two real roots
c. no real roots
d. no one real root​

Answer 1

Answer:

on factorisation using a^2 - b^2 = (a+b)(a-b)

we get (x^2 + 1 + x)(x^2 + 1 - x ) = 0

x^2 + x + 1 = 0 or x^2 - x + 1 = 0

both have no real roots as

in x^2 + x + 1 = 0 D = √ 1^2 - 4*1*1 = √ -3

and in x^2 - x + 1 = 0 D = √ (-1)^2 - 4*1*1= √-3

hence they have all the four imaginary roots

option C