q(y) = 2y – 3 Find the zeros of the polynomial.
Answers
Answered by
33
q (y) = 2y - 3
Solution :-
⇒2y - 3 = 0
⇒ 2y = 3
⇒ y = 3/2
⇒ y = 1.5
∴ The zero of q(y) will be 1.5
HOPE IT HELPS.
Solution :-
⇒2y - 3 = 0
⇒ 2y = 3
⇒ y = 3/2
⇒ y = 1.5
∴ The zero of q(y) will be 1.5
HOPE IT HELPS.
Answered by
13
Hi ,
Given polynomial Q(y)= 2y - 3 ,
is a linear polynomial in one
variable y .
So , it has only one zero .
To find zero ,
Let Q( y ) = 0
=> 2y - 3 = 0
=> 2y = 3
y = 3/2
Therefore ,
3/2 is zero of Q( y ).
Verification :
Substitute y = 3/2 in Q( y ), we get
Q( 3/2 ) = 2(3/2) - 3
= 3 - 3
= 0
I hope this helps you.
: )
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