Question

Q1. A Car X starts at 5 PM at a speed of 60 Kmhr Another Car Y starts from the same point at 6 20 PM at
a speed of 80 Km/hr Al what time will X and Y meet each other?​

Answer 1

At 10:20 car Y would have covered 320km ( dist= speed * time hence “dist = 80*4=320”)

At 10 car X would have covered 300km ( same calculation as tht of car Y )

And car X covers 60km per hour

Hence it covers 10 km per 10 min

Hence : at 10:20 car X would have covered 320km (300+10+10)

The 2 cars meet at 10:20 pm (provided they maintain the same avg speed )

Thank you …..

ʀᴇꜰᴇʀ ᴛᴏ ᴛʜᴇ ᴀᴛᴛᴄʜᴇᴍᴇɴᴛ.....

Answer 2

Step-by-step explanation:

At 10:20 car Y would have covered 320km ( dist= speed * time hence “dist = 80*4=320”)

At 10 car X would have covered 300km ( same calculation as tht of car Y )

And car X covers 60km per hour

Hence it covers 10 km per 10 min

Hence : at 10:20 car X would have covered 320km (300+10+10)

The 2 cars meet at 10:20 pm (provided they maintain the same avg speed )

Thank you …..