Q1 A card at random from ordinary pack of 52 playing cards. What is the probability of:
1.diamond
2.king
3.7 of heart
4. face cards
Q2 A pair of die is thrown. Find the probability of the following:
1. sum is 10
2. doublet
3. sum is less than 12
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no of diamonds=13
P(diamond) = 13 /52 = 1/4
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no of kings = 4
P(king) = 4/52 = 1/13
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7 of hearts = 1
P(7 of heart) = 1/52
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face of cards = 12
P(face of cards ) = 12/52
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sum is 10 = 3
P(sum is 10 ) = 3/36 = 1/13
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doublet = 6
P(doublet) =6/36 = 1/6
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sum less than 12
its sum less than 12 so 12 wont be included so only( 6,6) will be neglected
= 35
P(sum less than 12 ) =35/36
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P(diamond) = 13 /52 = 1/4
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no of kings = 4
P(king) = 4/52 = 1/13
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7 of hearts = 1
P(7 of heart) = 1/52
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face of cards = 12
P(face of cards ) = 12/52
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sum is 10 = 3
P(sum is 10 ) = 3/36 = 1/13
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doublet = 6
P(doublet) =6/36 = 1/6
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sum less than 12
its sum less than 12 so 12 wont be included so only( 6,6) will be neglected
= 35
P(sum less than 12 ) =35/36
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sahnianushka36:
Thankew for helping
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