Q1. (a) Divide:
9xcube – 6xsqare by 3x
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Answer:X³-6X²+9X+3 is divided by X-1
We get,
Quotient = X²-5X+4
and
Remainder = 7
FACTORIES THE QUOTIENT X²-5X+4
Then,
We get the zeros of the polynomial X²-5X+4
X²-5X+4
X²-4X-X +4
X(X-4) + 1 ( X-4)
(X-4) ( X+1)
X-4 = 0. X+1 = 0
X = 4. X = -1
Step-by-step explanation:
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