Question

Q1. A simple pendulum has time period of 1.6 s. What is its frequency?​

Answer 1

Answer:

Calculate the period of oscillations according to the formula above: T = 2π√(L/g) = 2π * √(2/9.80665) = 2.837 s . Find the frequency as the reciprocal of the period: f = 1/T = 0.352 Hz . You can also let this simple pendulum calculator perform all calculations for you!

Step-by-step explanation:

Answer 2

Answer:

1.6Hz

Step-by-step explanation:

Given :- t(time period )= 1.6s

To find:- f(frequency)

Solution:- f=1/t

f= 1/0.6

f= 1.6 Hz