Q1.Aakar a car accelerates uniformly from 18 kilometre per hour to 36 km per hour in 5 seconds calculate the acceleration and the distance covered by the car in that time.
Answers
Explanation:
✬ Acceleration = 1 m/s² ✬
✬ Distance Covered = 37.5 m ✬
Explanation:
Given:
Uniform velocity (u) of car is 18 km/h.
Final velocity (v) of car is 36 km/h.
Time take by car for acceleration is 5 seconds.
To Find:
What is the acceleration of car and distance covered by it ?
Formula to be used:
v = u + at
s = ut + 1/2at²
Solution: First , we need to change the velocity in m/s from km/h. For this multiply by 5/18.
u = 18 \times× 5/18 = 5 m/s.
v = 36 \times× 5/18 = 10 m/s.
Putting the values on formula
⟹ v = u + at
⟹ 10 = 5 + a \times× 5
⟹ 10 = 5 + 5a
⟹ 10 – 5 = 5a
⟹ 5 = 5a
⟹ 5/5 = a
⟹ 1 m/s² = a
Hence , The acceleration of the car is 1 m/s².
Now, For finding distance use the second formula:-
⟹ s = ut + 1/2at²
⟹ s = 5 \times× 5 + 1/2 \times× 1 \times× 5²
⟹ s = 25 + 25/2
⟹ s = 25 + 12.5
⟹ s = 37.5 m
Hence, the distance covered by car in that time is 37.5 m.