Question

Q1.Calculate the amount of NaOH required to produce 250ml of 5 Molar NaOH solution?​

Answer 1

Explanation:

Given:

250ml of 5 Molar NaOH solution has been provided.

To find:

Amount (i.e. mass) of NaOH required for the solution?

Calculation:

Now, we know that 5 M NaOH has 5 moles in 1 litre (i.e. 1000 mL) of solution.

So, moles of NaOH in 250 mL is:

$</p><p>= \dfrac{5}{1000} \times 250</p><p>$

$= \dfrac{5}{4}</p><p></p><p>$

$= 1.25 \: moles$

Now, mass of NaOH needed:

$mass = mole \times (molar \: mass)$

$\implies \: mass = 1.25 \times 40$

$\implies \: mass = 50 \: g$

So, 50 grams of NaOH is needed.

Answer 2

Answer:

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How many grams NaOH are present in 250 mL of 0.5 M NaOH solution?

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Video Explanation

Solution to Question ID 932242

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Answer

Correct option is

C

5g

No of moles (n) =

1000

Molarity×V

mL

Given:

M=0.5M

V

mL

=250mL

Therefore, n=

1000

0.5×250

=

1000

125

=0.125mol

Molar mass of NaOH = 40g

Mass of NaOH = 0.125×40=5g

Explanation:

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