Question

Q1) calculate the oxidation of underline atoms. 1) H2SO4​

Answer 1

Question

$\bold \purple{calculate \: the \: oxidation \: of \: underline \: atoms. 1)H _{2} {\underline \pink{S}}O _{4}}$

To find

oxidation number of sulphur...

Solution

let the number of Sulphur Be X

➙oxidation number of hydrogen= +1 ( non metals)

= -1 (metals)

➙ oxidation number of oxygen= -2 (generally )

$H _{2} {\underline \pink{S}}O _{4} \\ \to 1 \times 2 + x + ( - 2) \times 4 = 0 \\ \\ \to \: x - 6 = 0 \\ \\ \to \bold \orange{\: x = 6}$

therefore the oxidation number of Sulphur is +6

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MoRE information!!

✏️oxidation number is the charge present on atom in its anion state or expected to have in its covalent state.

✏️ hydrogen shows oxidation number + 1 with nonmetals and -1 with metals.

✏️oxygen shows oxidation number -2 generally... -1 in peroxide.... - 1/2 in superoxide

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