Question

Q1. Factorize by taking out common factor:

i) 2(2x - 5y) (3x + 4y) - 6(2x - 5y) (x - y)

Step-by-step explanation needed. NO SPAMMING!!! ​

Answer 1

ɢɪᴠᴇɴ : 2(2x-5ʏ)(3x+4ʏ)-6(2x-5ʏ)(x-ʏ)2(2x−5ʏ)(3x+4ʏ)−6(2x−5ʏ)(x−ʏ)

2(2x-5ʏ)(3x+4ʏ)-6(2x-5ʏ)(x-ʏ)2(2x−5ʏ)(3x+4ʏ)−6(2x−5ʏ)(x−ʏ)

=2 (2x - 5ʏ) (3x + 4ʏ) - 6 (2x - 5ʏ) (x - ʏ)=2(2x−5ʏ)(3x+4ʏ)−6(2x−5ʏ)(x−ʏ)

= (2x - 5ʏ) {2 (3x + 4ʏ) - 6 (x - ʏ)}=(2x−5ʏ)2(3x+4ʏ)−6(x−ʏ)

= (2x - 5ʏ) (6x + 8ʏ - 6x + 6ʏ)=(2x−5ʏ)(6x+8ʏ−6x+6ʏ)

= (2x - 5ʏ) (14ʏ)=(2x−5ʏ)(14ʏ)

= 14 (2x - 5ʏ) ʏ,=14(2x−5ʏ)ʏ,

ꜰᴀᴄᴛᴏʀɪᴢᴇ ꜰᴏʀᴍ ɪꜱ 14 (2x - 5ʏ) ʏ,14(2x−5ʏ)ʏ,

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