Question

Q1.
Find the area and perimeter of a A triaangle whose base in 6 cm each equal side is 5 cm and height 4 cm.
Q2.
Find the area and perimeter of an equilateral triangle who's each side is 5 cm.
Q3
Find the area of a rectangle whose length and breadth are 45 cm 16 cm respectively. Also, find
the perimeter of the rectangle.​

Answer 1

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Q1.

Find the area and perimeter of a A triaangle whose base in 6 cm each equal side is 5 cm and height 4 cm.

Ans: Base , b=6cm , Height , h = 4cm

=> Area of triangle = $\frac{1}{2}*b*h$ = 1/2 * 6 * 4

=> Area of triangle = 12 cm^2

Q2.

Find the area and perimeter of an equilateral triangle who's each side is 5 cm.

Ans : Side of equilateral Triangle = 5 cm

Area of equilateral triangle = $\frac{\sqrt{3} }{4}*(side)^2$

$\frac{\sqrt{3} }{4}*5^2\\\\ =>12.5*\sqrt{3} sq.uts\\\\=>10.825 cm^2$

Perimeter of equilateral triangle = 3*side=3*5=15cm

Q3

Find the area of a rectangle whose length and breadth are 45 cm 16 cm respectively. Also, find

the perimeter of the rectangle.

Ans: Length of rectangle = 45 cm

Breadth of rectangle = 16 cm

So, Area of rectangle = L*B=45*16=720cm^2

Perimeter of rectangle = 2(L+B)=2(45+16)

=>Perimeter of rectangle = 122 cm

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Answer 2

Answer:

Step-by-step explanation:

(1) Area of a triangle = 1/2 x base x height

                                  = 1/2 x 6 x 4

                                  = $\frac{24}{2} = 12$ cm²

(2) Side = 5 cm

   (i) Area of an equilateral triangle = $\frac{\sqrt{3} }4{}} (side)^{2}$

                                                       $= \frac{\sqrt{3} }4{}} (5)^{2}\\\\= \frac{\sqrt{3} }4{}} (25)\\\\= 6.25 \sqrt{3}$

   (ii) Perimeter of an equilateral triangle = 3 x side = 3 x 5 = 15 cm

(3)  l = 45 cm

     b = 16 cm

 (i) Area of rectangle = l x b = 45 x 16 = 720 cm²

(ii) Perimeter of rectangle = 2( l + b )

                                            = 2( 45 + 16)

                                            = 2( 61)

                                            = 122 cm