Question

Q1.Find the area of a triangle, two of whose sides are 18 cm and 10 cm and the perimeter is 42 cm

Answer 1

heya.......


hello friend



here a = 18 ,b = 10 c = ? '

perimeter = 42 

P = a + b+ c 

42 = 18 +10 + c

42 - 28 = c

..................... c= 14
Using Heron's formula,

S = a+ b + c/2 = P / 2 = 42/ 2 = 21

s- a = 21-18 = 3

s- b = 21 -10= 11

s-c = 21-14 = 7
A = ✓ S (s- a) (s- b) ( s-c)

= ✓ 21 × 3 × 11 × 7

=. 21 ✓ 11 cm².......


hope it helps you



tysm.....#gozmit

Answer 2

Answer:

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