Q4.Find the area of a quadrilateral ABCD in which AB = 24cm, BAD = 90ο and BCD forms an equilateral triangle each of whose side measures 26cm. ( √3 = 1.73)
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ABD is a right triangle. By the Pythagorean theorem, AB = 10.
area of ABD = 10·24/2 = 120 cm²
height of BCD = 13√3
area of BCD = 26·(13√3)/2 = 292.37 cm²
area of quadrilateral = 120 + 292.37 = 412.37 cm²
area of ABD = 10·24/2 = 120 cm²
height of BCD = 13√3
area of BCD = 26·(13√3)/2 = 292.37 cm²
area of quadrilateral = 120 + 292.37 = 412.37 cm²
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