Math, asked by priyam002964, 8 months ago

Q1. Find the area of a triangle whose perimeter is 180cm and its two sides are
80cm and 18 cm. Calculate the altitude of triangle corresponding to its shortest
side
Or​

Answers

Answered by mahi735
1

Answer:

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Step-by-step explanation:

perimeter =180cm

18+80+third side =180

98+ x =180

x=180-98

x=82 cm

2)take all sides like

a=18,b=80,c=82

s= perimeter/2 = 180/2=90

s-a =90-18=72

s-b=90-80=10

s-c=90-82=8

area = root s(s-a)(s-b)(s-c)

= root 90*72*10*8

=root 90*90*8*8

=720 square cm

3) shortest side =base =18 cm

area =720

1/2*base* altitude(h)= 720

h= 720*2/18

h=80cm

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