Question

Q1. Find the Hypotenuse of triangle whose base is 4 cm and perpendicular is 3 cm.
Q2. Find the length of rectangle whose breadth is 90 cm and breadth is 15 cm.
Q3. Find the average of 12,10,9,13,6.
Q4. In a rectangle the ratio of length and breadth is 2:3 and its perimeter is 120 cm. Find its Area

Answer 1

Answer:

1) 5 cm

2) question is not proper

3)12=6

10=5

9=4.5

13=6.5

6= 3

4) area = 3456

hope this will help you

Answer 2

Answer:

Answer (1)

Given :-

• Base of triangle = 4 cm
• Perpendicular line = 3 cm

To Find :-

Hypotenuse of triangle

Solution :-

According to Pythagoras theorem

$\huge \bf \: {h}^{2} = {p}^{2} + {b}^{2}$

Here,

H denotes Hypotenuse

P denotes Perpendicular

B denotes Base

$\tt \implies \: {H}^{2} = {3}^{2} + {4}^{2}$

$\tt \implies \: {H}^{2} = 9 + 16$

$\tt \implies \: {H}^{2} = 25$

$\tt \implies \: H = \sqrt{25}$

$\tt \implies \: H = 5 cm$

Hypotenuse of triangle is 5 cm

Answer (2)

Question to be asked

Find the length of rectangle whose perimeter is 90 cm and breadth is 15 cm.

Given :-

• Perimeter = 90 cm
• Breadth = 15 cm

To Find :-

Length

Solution :-

As we know that

Perimeter = 2(l + b)

Let the length be l

$\tt \implies \: 90 = 2(l \: + 15)$

$\tt \implies \: 90 = 2l \: + 30$

$\tt \implies \: 90 - 30 = 2l$

$\tt \implies \: 60 = 2l$

$\tt \implies \: l \: = \dfrac{60}{2} \:$

$\tt \implies \: l \: = 30 \: cm$

Hence,

The length of rectangle is 30 cm

Answer (3)

Given :-

Numbers :- 12,10,9,13,6.

To Find :-

Average

Solution :-

As we know that

$\bf \: Average \: = \dfrac{sum \: of \: observation}{total \: no \: of \: observation}$

$\tt \implies \: Average \: = \dfrac{12 + 10 + 9 + 13 + 6}{5}$

$\tt \implies \: Average \: = \dfrac{50}{5}$

$\tt \implies \: Average \: = 10$

The average of data is 10.

Answer (4)

Given :-

• ratio of length and breadth is 2:3
• perimeter is 120 cm.

To Find :-

Area

SoluTion :-

Firstly let's find the dimensions.

Let the ratio be 2x and 3x

$\tt \implies \: 120 = 2(2x + 3x)$

$\tt \implies \: 120 = 2(5x)$

$\tt \implies \: 120 = 10x$

$\tt \implies \: x = \dfrac{120}{10}$

$\tt \implies \: x = 12$

Dimensions will be

2x = 2(12) = 24

3x = 3(12) = 36

Let's find Area.

$\huge \bf \: Area = l \times b$

$\tt \implies Area \: = 24 \times 36$

$\tt \implies Area \: = 864 \: cm$