Question

Q1. Find the length of the axes, eccentricity and length of the latus-rectum of the hyperbola 25x2 – 36y2 = 225 ​

Answer 1

Answer:

The equation can be expressed as: The obtained equation is of the form Where, a = 3 and b = 5/2 Eccentricity is given by: Foci: The coordinates of the foci are (±ae, 0) (±ae, 0) = ±3 (√61/6) = ± √61/2 (±ae, 0) = (± √61/2, 0) The equation of directrices is given as: The length of latus-rectum is given as: 2b2/a ∴ Transverse axis = 6, conjugate axis = 5, e = √61/6, LR = 25/6, foci = (± √61/2, 0)Read more on Sarthaks.com - https://www.sarthaks.com/805933/find-the-axes-eccentricity-latus-rectum-and-the-coordinates-the-foci-the-hyperbola-25x-36y