Q1) Find the product of: (2x 2 + 3x − 7) and (3x2 − 5x + 4)
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16
Answer:
6x⁴−x³−28x²+47x−28
Step-by-step explanation:
(2x²+3x−7)(3x²−5x+4)
=(2x²+3x+−7)(3x²+−5x+4)
=(2x²)(3x²)+(2x²)(−5x)+(2x²)(4)+(3x)(3x²)+(3x)(−5x)+(3x)(4)+(−7)(3x²)+(−7)(−5x)+(−7)(4)
=6x⁴−10x³+8x²+9x³−15x²+12x−21x²+35x−28
=6x⁴−x³−28x²+47x−28
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