Question

Q1 Find the zeroes of polynomial x2
-6x +8 and verify the relationship between zeroes and coefficient

Answer 1

Step-by-step explanation:

p(x)=x²-6x+8

x²-6x+8

x²-4x-2x+8

x(x-4)-2(x-4)

(x-2)(x-4)

x=2, x=4

verification:-

sum of zeros = 4+2 = 6 -b/a=-(-6)/1=6

product of zeros = 2×4=8 c/a= 8/2=8

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