Question

Q1.Find the zeros of the following quadratic polynomial and verify the
relationship between zeros and the coefficient
t2-15

Answer 1

Step-by-step explanation:

Given:

→ t² - 15 = 0

→ (t)² - (√15)² = 0

Using identity a² - b² = (a + b)(a - b), we get:

→ (t + √15)(t - √15) = 0

By zero product rule:

→ (t + √15) = 0 or (t - √15) = 0

→ t = √15, -√15.

⊕ So, the zeros of the given equation are √15 and -√15.

Verification!

Comparing the given equation with ax² + bx + c = 0, we get:

→ a = 1

→ b = 0

→ c = -15

Here, sum of zeros = √15 - √15 = 0

Also, sum of zeros = -b/a = 0/1 = 0 (Verified)

Again, product of zeros = -√15 × √15 = -15

Also, product of zeros = c/a = -15/1 = -15 (Verified)