Q1. Given 5 cos A - 12 sin A= 0, find the value of (sin A + cos A) / (2 cos A - sin A)\
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Given: 5 cos A - 12 sin A= 0
To find: the value of (sin A + cos A) / (2 cos A - sin A)
Solution:
- Now we have given 5 cos A - 12 sin A = 0
- We can rewrite it as:
5 cos A = 12 sin A
5/12 = sin A / cos A
tan A = 5/12 = perpendicular /base
- Hypotenuse will be:
√p^2 + b^2 = √5^2 + 12^2
√169 = 13
sin A = 5/13 and cos A = 12/13
- So putting these values in given expression, we get:
( 5/13 + 12/13 )/( 2×12/13 - 5/13)
( 17/13 )/( 19/13 )
17/19
Answer:
So the value of given expression is 17/19
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