Q1-if a car attains a speed of 36km/h from rest in 12 minutes time,what is the distance covered?
Q2-a body is moving with a speed of 40km/h.one second later.it is moving at 58km/h?
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Q1-if a car attains a speed of 36km/h from rest in 12 minutes time,what is the distance covered?
Solution :
here u = 0 , v=36 km/hr t= 12 min
First convert velocity into m/s and time into seconds
therefore ,
v= 36*(1000 / 60 *60 ) m/s
= 10 m/s
Time = 12 min
= 12 *60 seconds
= 720 s
WE KNOW THAT
v=u+ at
10 = 0+a*720
a = 10/720 m/s²
= 1/72 m/s²
We know that ,
v² - u² = 2as
=> 10² - 0 ² = 2*(1/72 ) *s
=> 100 = s/36
=> s= 36*100
= 3600 m
Therefore Distance Traveled = 3600 m
Solution :
here u = 0 , v=36 km/hr t= 12 min
First convert velocity into m/s and time into seconds
therefore ,
v= 36*(1000 / 60 *60 ) m/s
= 10 m/s
Time = 12 min
= 12 *60 seconds
= 720 s
WE KNOW THAT
v=u+ at
10 = 0+a*720
a = 10/720 m/s²
= 1/72 m/s²
We know that ,
v² - u² = 2as
=> 10² - 0 ² = 2*(1/72 ) *s
=> 100 = s/36
=> s= 36*100
= 3600 m
Therefore Distance Traveled = 3600 m
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