Question

Q1.If p(x) = x+ 2 then find p(-2)?

Answer 1

Explanation:

Given

We have given function p(x)= x+2

To find

We have to find p(x) at p(-2)

$</p><p>\sf\huge {\underline{\underline{{Solution}}}} </p><p>Solution</p><p>$

We have given a function p(x)=x+2

Note : Any change in p(x) will cause a change in the function.

Now ,our function is p(x) and we have to find f(-2) now compare the coefficient of p(x) with p(-2) , we find x=-2

So,we have to find the value of p(x) at x=6

At x=-2 ,just put the given X's value into the p(x)

at x= -2

=>p(x)= x+2

=>p(-2)= -2+2

=>p(-2)=0

Therefore ,p(-2) is 0

Extra information=>

➥The above function is a linear equation as highest power is 1.

➥p(x)=y here ,p is the function and x is an input which gives output say 'y'.

➥We can find infinite number of output of p(x) by putting infinite number of values into p(x).

Answer 2

Answer:

0

Explanation:

p(x)=x+2

p(-2)=-2+2

=0

hence p(-2) is the zero of polynomial x+2