Q1. If (x + k) is a factor of 2x2 + 2kx + 5x + 10, ſind k.
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We have to find the value of k if (x + k) is a factor of p(x) = 2x² + (2k + 5)x + 10 = 0.
We know that if (x - a) is a factor of a polynomial f(x), then f(a) will be 0.
So, since (x + k) is a factor of p(x), then p(-k) will be 0. So,
p(-k) = 0
⇒ 2(-k)² + (2k + 5)(-k) + 10 = 0
⇒ 2k² - 2k² - 5k + 10 = 0
⇒ 10 - 5k = 0
⇒ 5k - 10 = 0
⇒ k - 2 = 0
⇒ k = 2
Hence, 2 is the answer.
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