Q1. Show that each angle of a rectangle is a right angle.
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Given: ABCD is a rectangle in which ∠A = 90.
To prove: ∠B = ∠C = ∠D = 90
Proof: AD || BC and AB is the transversal,
∴ ∠A + ∠B = 180 (Sum of adjacent interior angles is supplementary)
⇒ 90 + ∠B = 180
⇒ ∠B = 180 – 90 = 90
∠A = ∠C (Opposite angles of rectangle are equal)
∠B = ∠D (Opposite angles of rectangle are equal)
⇒ ∠A = ∠C = 90 and ∠B = ∠D = 90
∴∠A = ∠B = ∠C = ∠D = 90
Thus, each angle of rectangle is a right angle .
To prove: ∠B = ∠C = ∠D = 90
Proof: AD || BC and AB is the transversal,
∴ ∠A + ∠B = 180 (Sum of adjacent interior angles is supplementary)
⇒ 90 + ∠B = 180
⇒ ∠B = 180 – 90 = 90
∠A = ∠C (Opposite angles of rectangle are equal)
∠B = ∠D (Opposite angles of rectangle are equal)
⇒ ∠A = ∠C = 90 and ∠B = ∠D = 90
∴∠A = ∠B = ∠C = ∠D = 90
Thus, each angle of rectangle is a right angle .
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