prove that f'(a+b) = f'(a)+f'(b) if f(a)=x^2 and f(b)=x^3
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There seem to be some typing mistakes in the above qn
f(x) = x² f(y) = y³
f '(x) = 2 x f '(a) = 2 a
f '(a+b) = 2 (a+b) = 2 a + 2 b = f '(a) + f '(b)
The above relation does not hold good for f (x) = x³
as f '(x) = 3 x²
f '(a+b) = 3 (a+b)² = 3 a² + 3 b² + 6 ab = f '(a) + f '(b) + 6 a b
f(x) = x² f(y) = y³
f '(x) = 2 x f '(a) = 2 a
f '(a+b) = 2 (a+b) = 2 a + 2 b = f '(a) + f '(b)
The above relation does not hold good for f (x) = x³
as f '(x) = 3 x²
f '(a+b) = 3 (a+b)² = 3 a² + 3 b² + 6 ab = f '(a) + f '(b) + 6 a b
kvnmurty:
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