Question

Q1. Simplify the following.


$1. \: \: \frac{ {x }^{3 } + 8 }{ {x}^{2} - 4} \times \frac{x + 2}{ {x}^{2} - 2x + 4}$
plz plz plz solve step by step explaination (in orderwise)........


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Answer 1

Answer:

$\: \: \frac{ {x }^{3 } + 8 }{ {x}^{2} - 4} \times \frac{x + 2}{ {x}^{2} - 2x + 4} \\ \\ \frac{ {(x)}^{3} + {(2)}^{3} }{(x - 2)(x + 2)} \times \frac{(x + 2)}{ {x}^{2} - 2x + 4} \\ \\ \frac{ (x + 2)( {x}^{2} - 2x + 4) }{(x - 2)(x + 2)} \times \frac{(x + 2)}{( {x}^{2} - 2x + 4)} \\ \\ \frac{x + 2}{x - 2}$