Q1 . Subtract the sum of 13x – 4y + 7z and – 6z + 6x + 3y from the sum of 6x – 4y – 4z and 2x + 4y – 7
a ) –11x + y – 5z – 6
b ) –11x + y – 5z – 7
c ) 11x + y – 5z + 7
d ) –1x + y – 4z – 8
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Answer:
- 11x + y- 5z - 7
Step-by-step explanation:
sum of 13x – 4y + 7z and – 6z + 6x + 3y
= 13x – 4y + 7z – 6z + 6x + 3y
= 19x - y + Z. - - - - (1)
sum of 6x – 4y – 4z and 2x + 4y – 7
= 6x – 4y – 4z + 2x + 4y – 7
= 8x - 4z - 7 - - - - - - (2)
Subtracting (1) from (2)
= 8x - 4z - 7 - (19x - y+ Z)
= 8x - 4z - 7 - 19x + y - z
= - 11x + y- 5z - 7
Hope it helps you ☺️
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