Question

Q1.tell the equation of the line that goes through the points (-8, -1) and (4,-10)

Answer 1

Answer:

sjsuzbidbzwr,nee,ttnrwn5ewt'wnetwy'w463xnn5rwn6r6nw3n5nwne5n3wn3wne5n3nt,rn53nwnt,ej

Answer 2

Step-by-step explanation:

Answer:

To determine the equation of a straight line with 2 coordinates, we use the Two Point Form method.

According to the two point form method,

$\implies \dfrac{x-x_1}{y-y_1} = \dfrac{x_2-x_1}{y_2-y_1}$

where,

x₁, x₂, y₁, y₂ are the respective values of the two points given.

x, y are variables for determining the equation.

According to the question,

x₁ = -8, y₁ = -1

x₂ = 4, y₂ = -10

Substituting the values we get:

$\begin{gathered}\implies \dfrac{x-(-8)}{y-(-1)} = \dfrac{4 - (-8)}{-10 -(-1)}\\\\\\\implies \dfrac{(x+8)}{(y+1)} = \dfrac{4+8}{-10+1}\\\\\\\implies \dfrac{(x+8)}{(y+1)} = \dfrac{12}{-9}\\\\\\\text{Cross multiplying we get:}\\\\\implies -9(x+8) = 12(y+1)\\\\\implies -9x -72 = 12y + 12\\\\\implies 9x + 12y + 72 + 12 = 0\\\\\implies \boxed{ \bf{9x + 12y + 84 = 0}}\end{gathered}$

Hence the equation of the line passing through the points (-8,-1) and (4,-10) is 9x + 12y + 84 = 0.