Question

Q1.the angels of a triangle are in AP if the smallest angel is 50 find the other two angels?
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Answer 1

Explanation:

Given that

It is given that the smallest angle of a triangle is 50°.

To Find

we have to find the other two angles

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The smallest angle is 50

It means a is given we have to find the next two term means two angles.

The next two terms will be a+d and a+2d

So, 50+(50+d)+ (50+2d)

We find the all three angles

Property will used here :

➙In a Triangle the sum of all three angles makes 180°.

➙50+(50+d)+(50+2d)=180°

➙50+50+50+d+2d=180°

➙150+3d=180

➙3d=180-150

➙3d= 30

➙d=30÷3

➙d=10

Hence,the common difference is 10.

Let's finding the other two angles

50+d= 50+10=60°

50+2d=50+20=70°

Therefore,the all angles of a triangle are 50°,60° & 70° respectively.

Answer 2

Answer:

Property will used here :

➙In a Triangle the sum of all three angles makes 180°.

➙50+(50+d)+(50+2d)=180°

➙50+50+50+d+2d=180°

➙150+3d=180

➙3d=180-150

➙3d= 30

➙d=30÷3

➙d=10