Question

Q1.The length of a rectangle in twice its breadth . If the perimeter is 36 meters , find the length and breadth of the rectangle.​

Answer 1

Explanation:

Given :

Length of a Rectangle is twice its breadth .

Perimeter of the Rectangle is 36 m .

To Find :

Length and Breadth of the Rectangle .

Solution :

\longmapsto\tt{Let\:Breadth\:be=x}⟼LetBreadthbe=x

As Given that length of a rectangle is twice its breadth .

So ,

\longmapsto\tt{Length=2x}⟼Length=2x

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}</p><p></p><p> </p><p>$

Putting Values :

\longmapsto\tt{36=2(2x+x)}⟼36=2(2x+x)

$\longmapsto\tt{\cancel\dfrac{36}{2}=3x}$

$\longmapsto\tt{18=3x}</p><p>$

$\longmapsto\tt{x=\cancel\dfrac{18}{3}}</p><p> </p><p>$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{x}\orange{=}\purple{6}}}</p><p></p><p> </p><p> </p><p> </p><p> </p><p>$

Therefore :

$\longmapsto\tt{Breadth\:of\:Rectangle=x}</p><p>$

$\longmapsto\tt\bf{6\:m}</p><p>$

$\longmapsto\tt{Length\:of\:Rectangle=2(6)}$

$\longmapsto\tt\bf{12\:m}$

Answer 2

Answer:

length=32

breadth=

$4 \sqrt{8}$