Q1.the sum of the digit of a two digit number is 8. if the number formed by reversing the digits is less than original number by 18.Find the original number.
Answers
Explanation:
Given
Sum of the digit of a two digit number is 8
Number obtained by reversing the digits is less than the original number by 18.
To Find
We have to find the original number.
SOLUTION:
Let the digits be 'x' and y where x is at unit place and y is at tens place
The number formed is : 10y +x
Number obtained Through reversing the order of digits : 10x+y
According to the question
Reversed number is less than the original number by 18
➾10y+x-(10x+y)=18
➾10y+x-10x-y=18
➾9y-9x=18
➾9(y-x)=18
➾y-x=2--------------(1)
Also,the sum of its digits is 8
So, x+y=8-----------(2)
Adding Equation 1 and 2
➾y-x+x+y=2+8
➾2y=10
➾y=5
put y's value in Equation 2
➾x+y=8
➾x+5=8
➾x=8-5=3
x=3
Let's finding the number
Original number :10y+x= 10(5)+3=53
Obtained by reversing the digits:10x+y=30+5=35.
Answer:
It is given that sum of the digits,that is x and y, is 8. Therefore we can state, x+y = 8. When we reverse (xy) it becomes (yx), in expanded form it can be written as (10y + x). Again it is given that difference between the two numbers is 18.