Physics, asked by itzpappu, 2 months ago

Q1.the sum of the digit of a two digit number is 8. if the number formed by reversing the digits is less than original number by 18.Find the original number​.

Answers

Answered by oObrainlyreporterOo
3

Explanation:

Given

Sum of the digit of a two digit number is 8

Number obtained by reversing the digits is less than the original number by 18.

To Find

We have to find the original number.

SOLUTION:

Let the digits be 'x' and y where x is at unit place and y is at tens place

The number formed is : 10y +x

Number obtained Through reversing the order of digits : 10x+y

According to the question

Reversed number is less than the original number by 18

➾10y+x-(10x+y)=18

➾10y+x-10x-y=18

➾9y-9x=18

➾9(y-x)=18

➾y-x=2--------------(1)

Also,the sum of its digits is 8

So, x+y=8-----------(2)

Adding Equation 1 and 2

➾y-x+x+y=2+8

➾2y=10

➾y=5

put y's value in Equation 2

➾x+y=8

➾x+5=8

➾x=8-5=3

x=3

Let's finding the number

Original number :10y+x= 10(5)+3=53

Obtained by reversing the digits:10x+y=30+5=35.

Answered by vineeth121269
0

Answer:

It is given that sum of the digits,that is x and y, is 8. Therefore we can state, x+y = 8. When we reverse (xy) it becomes (yx), in expanded form it can be written as (10y + x). Again it is given that difference between the two numbers is 18.

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