Question

Q10. An electric heater draws 1000 W from a 250 V

source. What power does it take from a 208 V

source? What is the resistance of the heater?

Answer 1

HOLA!!!

________________

HERE'S YOUR ANSWER

GIVEN THAT

Power = 1000W = 1kW is drawn from 250V

Power = V × I

I = Power / V

= 1kW/250

I = 0.004A

Now new Power drawn from 208V

Power = V × I

= 208 × 0.04

= 8.32 kW

Therefore power drawn = 8.32kW

Answer 2

FINAL POWER OUTPUT WILL BE 692.22 WATTS.

Given:

• 1000 watt power output of a heater from a 250 volt source.

• Now, the heater is connected to a 208 volt source.

To find:

• The power output ?

Calculation:

First of all, let us calculate the resistance of the heater:

$P = \dfrac{{ V}^{2}}{R}$

$\implies R = \dfrac{{ V}^{2}}{P}$

$\implies R = \dfrac{250 \times 250}{1000}$

$\implies R =62.5 \: ohm$

Now, when the heater will be connected to the new voltage source, the power output will be:

$P_{new} = \dfrac{{ (V_{2})}^{2}}{R}$

$\implies P_{new} = \dfrac{{ (208)}^{2}}{62.5}$

$\implies P_{new} = 692.22 \: watt$

So, new power output by the heater will be 692.22 watt.