Question

Q10) How much heat energy is necessary to raise the temperature of 5 kg of water from 200
C to 100 0 C
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Answer 1

Quantity of heat required to raise 5 kg of water from 20 0C  to 1000C is given by the formula:Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.)For water, the value of .C  is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C.

Answer is  266.858kj1 calorie = 4.18 Joules. Thus 4180 Joules of energy of heats required for  a Kilogram of water through just one degree  centigrade.

Answer 2

Answer:

1680KJ

Step by step Explanation:

Given :

Mass =5kg

T1=20∘C,T2=100∘C

ΔT=100−20=80∘C

Q=m×C×ΔT

where C= specific heat capacity of water = 4200J/(kgK)

Q=5×4200×80

=1680000 Joule.

=1680KJ

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