Q10. The distance between the school and the house of Seema is 1 km 375m. Every day she walks both the ways. Find the total distance covered by her in five days.
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Answered by
0
distance covered by Seema in one day = 1375 × 2 = 2750 m
distance covered by Seema in 5 days = 2750 × 5 = 13750 m
therefore, total distance covered by Seema is 13 km 750 m .
distance covered by Seema in 5 days = 2750 × 5 = 13750 m
therefore, total distance covered by Seema is 13 km 750 m .
Answered by
4
Everyday, she walks => 2(1 km 375m)
Everyday, she walks =>2(1000+375)m
Everyday, she walks => 2(1375) = 2750m
××××××××××××××××××××××××××××
Distance covered in 5 days = 5(2750)m
Distance covered in 5days = 13,750 m = 13km750m
I hope this will help you
(-:
Everyday, she walks =>2(1000+375)m
Everyday, she walks => 2(1375) = 2750m
××××××××××××××××××××××××××××
Distance covered in 5 days = 5(2750)m
Distance covered in 5days = 13,750 m = 13km750m
I hope this will help you
(-:
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