Math, asked by Anonymous, 10 months ago

Q10 using identity no vii

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Answered by Anonymous
2

Answer:

\boxed{Your\:Solution}

Step-by-step explanation:

=(x)^{3} +(2y)^{3} +3\:X x^2 X\:2y + 3\:X\:x\:X\:2y^2

=(x+2y)^{3} [a^{3} +b^{3} +3a^{2} b+3ab^{2} =a+b^{2} ]

=(x+2y)(x+2y)(x+2y)

∴   x^{3} +8y^{3} +6x^{2} y+12x^{2} =(x+2y)(x+2y)(x+2y)

\boxed{Hope\:it\:Helps}

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