Question

Q10) What mass of slaked lime would be required to decompose completely 4 g of NH4Cl and what would be the mass of each product?

Answer 1

The reaction for the decomposition of the Slaked lime and Calcium Hydroxide is ⇒

2NH₄Cl + Ca(OH)₂ --------→ CaCl₂ + 2H₂O + 2NH₃↑

Molar mass of the NH₄Cl = 53.5 g/mole.
Molar mass of the Ca(OH)₂ = 74 g/mole.
Molar mass of CaCl₂ = 111
Molar mass of water = 18 g/mole.
Molar mass of Ammonia = 17 g/mole.

From the Reaction,
∵ 2 × 53.5 grams of NH₄Cl requires 74 g of the Ca(OH)₂
∴ 1 g of NH₄Cl requires 74/107 g of the Ca(OH)₂.
∴ 4 g of the NH₄Cl requires 0.692 × 4 g of the Ca(OH)₂.
    = 2.768 g of the Ca(OH)₂

Thus, Mass of the Calcium Hydroxide is 2.768 grams.

For the Mass of the CaCl₂.
∵ 2 × 53.5 g of the Ammonium Chloride produces 111 g of Calcium Chloride.
∴ 1 g of the ammonium ch. produces 111/107 g of CaCl₂.
∴ 4 g of NH₄Cl produces 1.04 × 4 g = 4.16 g of CaCl₂ 

For the mass of water,
107 g of Ammonium chloride produces 2 × 18 g of Water.
∴ 4 g of the Ammonium chloride produces 36/107 × 4 = 1.356 g of water.

For the Mass of Ammonia,
107 g of Ammonium Chloride produces 2 × 17 g of Ammonia.
∴ 1 g of Ammonium Chloride produces 34/107 g of Ammonia.
∴ 4 g of NH₄Cl produces 34/107 × 4 = 1.27 g of NH₃.


Hope it helps.

Answer 2

What mass of slaked lime would be required to decompose completely 4 g of NH4Cl and what would be the mass of each product?

now the answer is ....

The reaction for the decomposition of the Slaked lime and Calcium Hydroxide is ⇒

2NH₄Cl + Ca(OH)₂ --------→ CaCl₂ + 2H₂O + 2NH₃↑

Molar mass of the NH₄Cl = 53.5 g/mole.

Molar mass of the Ca(OH)₂ = 74 g/mole.

Molar mass of CaCl₂ = 111

Molar mass of water = 18 g/mole.

Molar mass of Ammonia = 17 g/mole.

From the Reaction,

∵ 2 × 53.5 grams of NH₄Cl requires 74 g of the Ca(OH)₂

∴ 1 g of NH₄Cl requires 74/107 g of the Ca(OH)₂.

∴ 4 g of the NH₄Cl requires 0.692 × 4 g of the Ca(OH)₂.

  = 2.768 g of the Ca(OH)₂

Thus, Mass of the Calcium Hydroxide is 2.768 grams.

For the Mass of the CaCl₂.

∵ 2 × 53.5 g of the Ammonium Chloride produces 111 g of Calcium Chloride.

∴ 1 g of the ammonium ch. produces 111/107 g of CaCl₂.

∴ 4 g of NH₄Cl produces 1.04 × 4 g = 4.16 g of CaCl₂ 

For the mass of water,

107 g of Ammonium chloride produces 2 × 18 g of Water.

∴ 4 g of the Ammonium chloride produces 36/107 × 4 = 1.356 g of water.

For the Mass of Ammonia,

107 g of Ammonium Chloride produces 2 × 17 g of Ammonia.

∴ 1 g of Ammonium Chloride produces 34/107 g of Ammonia.

∴ 4 g of NH₄Cl produces 34/107 × 4 = 1.27 g of NH₃.

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