Question

Q11.Fi find the probability of getting, (1). multiple of 3., (2). not a prime number

Answer 1

$(1) \: p \: of \: multiple \: of \: 3 = \frac{40 + 30}{200} = \frac{7}{20} \\ (2)p \: of \: not \: a \: prime \: no. = \frac{25 + 28 + 30}{200} = \frac{83}{200}$

Answer 2

1 ) probability of getting multiple of 3 = 40/200= 1/5

probability of not getting a prime number= (25+28+30)/200
= 83/200