Q12 A fluoride of oxygen was prepared by mixing oxygen and fluorine in the proper
ratio at 60K. This compound contains 32.1 % Fand 67.9 % O. What is the
empirical formula of the compound
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Answer:
O5F2.
Explanation:
Element Flourine and oxygen
percentage by mass F=32.1%,O=67.9%
Relative no. of moles of F, 32.1÷19=1.64.and O ,67.9÷10=4.29.
Simple ratio of moles F,1.64%1.64=1 and O ,4.24÷1.64=2.50
Some whole ratio F=1×2=2
O=2.5 ×2=5.
Simples whole number ratio is 2:5 .
Hence the empirical formula of compound is O5F2.
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