Question

Q12. Calculate no of electrons present in 51g NH3​

Answer 1

Answer:

Number of electrons in Nitrogen = 7

Number of electrons in 3 times hydrogen =3

Number of electrons in 1 mole of NH3=7+3=10

Number of given moles of NH3= 51/17 =3

So , Number of electrons in 3 moles of NH3= No. of electrons in 51g of NH3 = 3×10 =30

hope you got your answer...

Answer 2

Answer:

Explanation:

electrons present in N = 7

electrons present in H = 3 × 1 = 3

total electrons = 7 + 3 = 10

molar mass of NH₃ = 14 + 3 × 1

= 14 + 3

=17 g

moles = mass/molar mass

=51/17

=3 mol

no of electrons = moles × total no of electrons × Na (Avogadro's no.)

= 3 × 10 × 6.022 × 10²³

=18.066 × 10²⁴

=1.8066 × 10²⁵ electrons