Question

Q12
In figure, if AB || CD and CD || EF, find angle ACE.
Angle BAC= 80
Angle CEF= 150

Answer 1

Here the answer,

Since AB||CD

We can say 80° = angle ACD .... alternate angles

and angle ACD = angle ACE + angle ECD

therfore

angle ACE + angle ECD = 80°

angle ACE = 80° - angle ECD... eqn 1

And CD||EF

therefore

150° + angle ECD = 180° ... interior angles

angle ECD = 180° - 150°

= 30°

put angle ECD = 30° in eqn 1

angle ACE = 80° - 30°

angk ACE = 50°

Answer 2

Answer:

refer to the attachment!!