Math, asked by adimkhan, 4 months ago


Q12 In the year 2012, the average age of a family of 3 members was 18 years. Two children having been born (with age
difference of 4 years), the present sum of age of the family is 90 years. The present age of the youngest child is :
(a) 1
(b) 2.
(C) 3
(d) 4​

Answers

Answered by lalitnit
0

Answer:

the average age of a family of 3 members was 18 yrs

The sum of it is = 18*3 =54

present sum of age of the family is 90 years

54 + x + x-4 = 90

2x - 4 =90-54

2x = 36+4 = 40

x = 20

x-4 = 16

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