Q12 urgent pls help
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As we know , if a,b,c are in AP .
Then, b-a = c-b.
Now,
For 3^a ,3^b,3^c be in GP ,
3^b/3^a = 3^c /3^b
i.e. 3^(b-a) = 3^(c-b)
And, we already know b-a = c-b , so, the above equation will be equal.
Thus, 3^a ,3^b,3^c are in GP.
Then, b-a = c-b.
Now,
For 3^a ,3^b,3^c be in GP ,
3^b/3^a = 3^c /3^b
i.e. 3^(b-a) = 3^(c-b)
And, we already know b-a = c-b , so, the above equation will be equal.
Thus, 3^a ,3^b,3^c are in GP.
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I hope this helps you
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