Question

Q13. A car falls of a ledge and drops to the ground in 0.5 sec (Take g=10 m/sec)

a. What is the speed on striking the ground?

b. What is the average speed during 0.5 sec?

c. How high is the ledge from the ground?

plz answer fast
the best answer will be marked brainest

Answer 1

from first law of motion
V =u+at

1)Given:-
a=10m/s^2
v=?
u=0
substituting the above value we get
V = 5m/s

2)avrg speed= Total distance travelled/ time taken
=1.25/0.5
=2.5m/s

3) by using third law of motion we can find height of Ledge
s=ut+1/2at^2
using the formula we get height is 1.25 m
hope so it will help you all the best

Answer 2

ok now see.
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