Q13. In a transformer no of turns in
the primary coil is 140 and that in th
secondary coil is 280. If current in
primary is 4A, the current in
secondary is *
Answers
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0
Answer:
8A
Explanation:
- We know, N¹/N²=V¹/V²=I¹/I²
- so,140/280=4/I². here,N¹=140,N²=280,I¹=4
- l²=8A
hope,I have helped you.
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