Q13. Sum of two angles of a triangle is 90° and their difference is 50°. Find all the angles
of the triangle.
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CherrySharma152003:
Ty..!!
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Let the angles are x,y,Z.
ATQ
x+y=90
x-y=50
On solving both by elimination method
x=70
y=20
Also sum of all angles of a triangle is 180.
So,
x+y+z=180
Put values of x and y
So, z=90
ATQ
x+y=90
x-y=50
On solving both by elimination method
x=70
y=20
Also sum of all angles of a triangle is 180.
So,
x+y+z=180
Put values of x and y
So, z=90
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