Question

Q14. A pole 6m high casts a shadow 2root 3m long on the ground, then the Sun's attitude at
that time is.

Answer 1

Answer:

Hello mate✌✌✌

Kindly refer to the attachment.

Hope it helps✌✌✌

Answer 2

SOLUTION:-

Given:

The height (h)or perpendicular (p) of the pole is 6m & base (b) is 2√3.

Therefore,

Let the angle of the shadow is theta

we know that,

$tan \theta = \frac{p}{b} \\ \\ tan \theta = \frac{6}{2 \sqrt{3} } = \frac{3}{ \sqrt{3} } \\ \\ tan \theta = \frac{3 \times \sqrt{3} }{ \sqrt{3}\times \sqrt{3} } \\ \\ tan \theta = \frac{3 \sqrt{3} }{3} \\ \\ tan \theta = \sqrt{3} \\ \\ = > \theta = 60 \degree$

Hope it helps ☺️