Math, asked by kavyapanwar28, 4 months ago


Q15)Find the remainder when p(x)=x2-ax?+6x-a is divided by (x-a).
Auctions of 3 m​

Answers

Answered by XxZeeshanarshiALLHA
0

Answer:

Here, p(x)=x

3

+ax

2

+6x−a, and the zero of x−a is a

So, p(a)=a

3

+a×a

2

+6×a−a

=2a

3

+5a

So, by the Remainder Theorem, 2a

3

+5a is the remainder when x

3

+ax

2

+6x−a is divided by x−a.

Answered by walisyed696
0

464349646491967618461

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